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1.5x^2-1.5x=20
We move all terms to the left:
1.5x^2-1.5x-(20)=0
a = 1.5; b = -1.5; c = -20;
Δ = b2-4ac
Δ = -1.52-4·1.5·(-20)
Δ = 122.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.5)-\sqrt{122.25}}{2*1.5}=\frac{1.5-\sqrt{122.25}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.5)+\sqrt{122.25}}{2*1.5}=\frac{1.5+\sqrt{122.25}}{3} $
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